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5x^2-25x-2730=0
a = 5; b = -25; c = -2730;
Δ = b2-4ac
Δ = -252-4·5·(-2730)
Δ = 55225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{55225}=235$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-235}{2*5}=\frac{-210}{10} =-21 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+235}{2*5}=\frac{260}{10} =26 $
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